You pick airway, oxygen, and breathing actions in the order a nurse actually moves. Five of the 15 questions include the correct answer and rationale. The other ten keep answers in the study hub. Continue with the LPN exams exam guide or more LPN exams practice questions.
Five respiratory questions with answers
Cover the key. Write the first action. Then open the rationale and name why the other choices fail.
Question 1
Which of the following is the most factor that can increase the volume of air entering the lung?
A. Increase in the pressure gradient
B. Increase in action potential
C. Both a+b
D. Decrease in the pressure gradient
Show answer and rationale
Correct answer: A — Increase in the pressure gradient
The volume of air entering the lung during inspiration is driven by Boyle's law: lung volume increases as intrapulmonary pressure decreases relative to atmospheric pressure. This pressure gradient is created by the diaphragm and intercostal muscles contracting, expanding the thoracic cavity, and dropping intrapulmonary pressure (e.g., from 760 mmHg to 758 mmHg), allowing air to flow in. Increasing this gradient via greater muscle contraction or thoracic expansion directly increases inspired volume, making it the primary factor. Increase in action potential' is vague but likely refers to neural impulses to respiratory muscles; while more frequent or intense action potentials could enhance muscle effort, this is secondary to the mechanical pressure gradient they produce. Combining both doesn't elevate action potentials to equal status, as pressure is the direct mechanism. Decreasing the gradient reduces airflow, opposing the goal. Thus, the pressure gradient is the most critical factor, as it's the physical driver of ventilation, rooted in respiratory mechanics.
Question 2
Compared to a normal individual, a patient with idiopathic pulmonary fibrosis, one of the following is expected to be more than normal?
A. TLC
B. Total pulmonary vascular resistance
C. FEV1
D. PaO2
Show answer and rationale
Correct answer: B — Total pulmonary vascular resistance
Idiopathic pulmonary fibrosis (IPF) is a restrictive lung disease marked by progressive scarring of the lung interstitium, reducing lung elasticity and function. Total lung capacity (TLC) decreases in IPF because fibrotic tissue stiffens the lungs, limiting their expansion. Forced expiratory volume in 1 second (FEV1) and forced vital capacity (FVC) are both reduced, but the FEV1/FVC ratio remains normal or elevated, unlike in obstructive diseases. Arterial oxygen partial pressure (PaO2) drops due to impaired gas exchange across thickened alveolar walls, leading to hypoxemia. However, total pulmonary vascular resistance (PVR) increases in IPF as fibrosis compresses and obliterates pulmonary capillaries, narrowing the vascular bed and elevating resistance to blood flow. This increase can strain the right heart, potentially causing cor pulmonale. Among the options, only total pulmonary vascular resistance is expected to be higher than normal, aligning with IPF's impact on the pulmonary vasculature rather than lung volumes or oxygenation, which decline.
Question 3
Compared to a normal individual, a patient with idiopathic pulmonary fibrosis, one of the following is expected to be more than normal?
A. TLC
B. Total pulmonary vascular resistance
C. FEV1
D. PaO2
Show answer and rationale
Correct answer: B — Total pulmonary vascular resistance
Idiopathic pulmonary fibrosis (IPF) is a restrictive lung disease marked by progressive scarring of the lung interstitium, reducing lung elasticity and function. Total lung capacity (TLC) decreases in IPF because fibrotic tissue stiffens the lungs, limiting their expansion. Forced expiratory volume in 1 second (FEV1) and forced vital capacity (FVC) are both reduced, but the FEV1/FVC ratio remains normal or elevated, unlike in obstructive diseases. Arterial oxygen partial pressure (PaO2) drops due to impaired gas exchange across thickened alveolar walls, leading to hypoxemia. However, total pulmonary vascular resistance (PVR) increases in IPF as fibrosis compresses and obliterates pulmonary capillaries, narrowing the vascular bed and elevating resistance to blood flow. This increase can strain the right heart, potentially causing cor pulmonale. Among the options, only total pulmonary vascular resistance is expected to be higher than normal, aligning with IPF's impact on the pulmonary vasculature rather than lung volumes or oxygenation, which decline.
Question 4
Which of the following structures contains blood with the highest PCO2?
A. Carotid bodies
B. Pulmonary veins
C. Superior vena cava
D. The midportion of pulmonary capillaries
Show answer and rationale
Correct answer: C — Superior vena cava
PCO2, or partial pressure of carbon dioxide, reflects the concentration of CO2 in blood, highest where metabolic waste accumulates and lowest where gas exchange removes it. The superior vena cava (SVC) carries deoxygenated blood from the upper body back to the heart, rich in CO2 from tissue metabolism, typically with a PCO2 of 45-46 mmHg, making it the highest among the options. Pulmonary veins carry oxygenated blood from the lungs to the heart after CO2 is offloaded in the alveoli, so their PCO2 is low (around 40 mmHg, arterial level). The midportion of pulmonary capillaries is where gas exchange occurs, transitioning from high venous PCO2 to lower arterial levels, averaging less than the SVC. Carotid bodies are chemoreceptors sensing blood gases, not a blood-containing structure, but even arterial blood they monitor has a PCO2 of about 40 mmHg. The SVC, as a major venous return vessel, consistently has the highest PCO2 due to its role in collecting metabolically produced CO2 before pulmonary gas exchange, distinguishing it from the other options.
Question 5
Which of the following structures contains blood with the highest PCO2?
A. Carotid bodies
B. Pulmonary veins
C. Superior vena cava
D. The midportion of pulmonary capillaries
Show answer and rationale
Correct answer: C — Superior vena cava
PCO2, or partial pressure of carbon dioxide, reflects the concentration of CO2 in blood, highest where metabolic waste accumulates and lowest where gas exchange removes it. The superior vena cava (SVC) carries deoxygenated blood from the upper body back to the heart, rich in CO2 from tissue metabolism, typically with a PCO2 of 45-46 mmHg, making it the highest among the options. Pulmonary veins carry oxygenated blood from the lungs to the heart after CO2 is offloaded in the alveoli, so their PCO2 is low (around 40 mmHg, arterial level). The midportion of pulmonary capillaries is where gas exchange occurs, transitioning from high venous PCO2 to lower arterial levels, averaging less than the SVC. Carotid bodies are chemoreceptors sensing blood gases, not a blood-containing structure, but even arterial blood they monitor has a PCO2 of about 40 mmHg. The SVC, as a major venous return vessel, consistently has the highest PCO2 due to its role in collecting metabolically produced CO2 before pulmonary gas exchange, distinguishing it from the other options.
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Question 6
What is expected in a premature baby with IRDS? T=alveolar surface tension, C=lung compliance, PaO2=arterial PO2?
A. T: Increase, C: increase, PaO2: increase
B. T: Increase, C: decrease, PaO2: decrease
C. T: Decrease, C: decrease, PaO2: equal
D. T: Increase, C: increase, PaO2: decrease
Correct answer:
Infant respiratory distress syndrome (IRDS), or hyaline membrane disease, occurs in premature infants due to insufficient surfactant production by immature type II alveolar cells. Surfactant lowers alveolar surface tension (T), facilitating lung expansion. In IRDS, reduced surfactant leads to increased surface tension, causing alveoli to collapse (atelectasis) after each breath. This high tension decreases lung compliance (C), as the lungs become stiffer and harder to inflate, requiring greater pressure for ventilation. Consequently, collapsed alveoli impair gas exchange, reducing arterial oxygen partial pressure (PaO2) below normal (hypoxemia), often to levels like 50-60 mmHg instead of the typical 75-100 mmHg. The correct combination increased T, decreased C, decreased PaO2 reflects the pathophysiology of IRDS, where surfactant deficiency drives a cascade of respiratory challenges. Other combinations, like increased compliance or unchanged PaO2, contradict the condition's mechanics, where stiff lungs and poor oxygenation are hallmark features.
Diffusion rate, per Fick's law, depends on surface area (choice A), concentration gradient (choice B), solubility (choice C), and membrane thickness (choice E), but not directly on molecular weight of gas (choice D), making D correct. Surface area increases diffusion by providing more space for gas exchange, as seen in alveoli. The concentration gradient (partial pressure difference) drives diffusion, e.g., Oâ‚‚ from alveoli to blood. Solubility affects how easily gases dissolve in the membrane, with COâ‚‚ diffusing faster than Oâ‚‚ due to higher solubility. Thickness inversely affects rate; thinner alveolar walls enhance diffusion. Molecular weight influences diffusion speed in free gas (Graham's law), but in the lung's aqueous environment, solubility dominates over molecular weight for Oâ‚‚ and COâ‚‚ exchange across membranes. Studies show diffusion capacity correlates with solubility and pressure gradients, not molecular weight, in physiological contexts, confirming D as the factor least affecting diffusion rate here.
What is expected in a premature baby with IRDS? T=alveolar surface tension, C=lung compliance, PaO2=arterial PO2?
A. T: Increase, C: increase, PaO2: increase
B. T: Increase, C: decrease, PaO2: decrease
C. T: Decrease, C: decrease, PaO2: equal
D. T: Increase, C: increase, PaO2: decrease
Correct answer:
Infant respiratory distress syndrome (IRDS), or hyaline membrane disease, occurs in premature infants due to insufficient surfactant production by immature type II alveolar cells. Surfactant lowers alveolar surface tension (T), facilitating lung expansion. In IRDS, reduced surfactant leads to increased surface tension, causing alveoli to collapse (atelectasis) after each breath. This high tension decreases lung compliance (C), as the lungs become stiffer and harder to inflate, requiring greater pressure for ventilation. Consequently, collapsed alveoli impair gas exchange, reducing arterial oxygen partial pressure (PaO2) below normal (hypoxemia), often to levels like 50-60 mmHg instead of the typical 75-100 mmHg. The correct combination increased T, decreased C, decreased PaO2 reflects the pathophysiology of IRDS, where surfactant deficiency drives a cascade of respiratory challenges. Other combinations, like increased compliance or unchanged PaO2, contradict the condition's mechanics, where stiff lungs and poor oxygenation are hallmark features.
Fick's law depend on multiple factors, which one of them will have the most effect when observing the diffusion of different gases?
A. Partial pressure gradient
B. Temperature
C. Diffusion distance
D. Diffusion coefficient
Correct answer:
Fick's law of diffusion states that the rate of gas diffusion across a membrane (e.g., alveolar-capillary) is proportional to the surface area (A), diffusion coefficient (D), and partial pressure gradient (ÃŽâ€P), and inversely proportional to diffusion distance (d): Rate = (A × D × ÃŽâ€P) / d. When comparing different gases (e.g., O2 vs. CO2), the diffusion coefficient (D) varies most significantly, as it depends on gas solubility and molecular weight (D ∠solubility / √MW). CO2's solubility is ~20 times higher than O2's (0.51 vs. 0.024 ml/mmHg/L), though O2's molecular weight is slightly lower (32 vs. 44), making CO2 diffuse ~20 times faster despite similar gradients. Partial pressure gradient drives diffusion but is gas-specific and often comparable (e.g., O2: 100-40 mmHg, CO2: 46-40 mmHg). Temperature and distance affect all gases similarly in the lung. Thus, the diffusion coefficient has the most pronounced effect across different gases, explaining why CO2 equilibrates faster than O2 across the respiratory membrane.
A nurse obtains the health history of a client who is recently diagnosed with lung cancer and identifies that the client has a 60–pack-year smoking history. Which action is most important for the nurse to take when interviewing this client?
A. Tell the client that he or she needs to quit smoking to stop further cancer development.
B. Encourage the client to be completely honest about both tobacco and marijuana use.
C. Maintain a nonjudgmental attitude to avoid causing the client to feel guilty.
D. Avoid giving the client false hope regarding cancer treatment and prognosis.
Correct answer:
The correct answer is C: Maintain a nonjudgmental attitude to avoid causing the client to feel guilty. This is important because the nurse needs to establish trust with the client to obtain accurate information about their health history. Being nonjudgmental creates a safe space for the client to share openly, which is crucial for effective assessment and planning of care.
Choice A is incorrect because while it is important for the client to quit smoking, addressing this issue at the first encounter may not be the most effective approach and could potentially alienate the client.
Choice B is also incorrect as the focus should be on building rapport and obtaining accurate information relevant to the client's current health status. Encouraging honesty about substance use is important but not the most critical action in this context.
Choice D is incorrect as the nurse should provide information and support to the client based on the client's needs and wishes, rather than making assumptions about their preferences or prognosis.
Regarding pulmonary vascular resistance, which one of the following is true?
A. Is low at high lung volumes
B. Is low at low lung volumes
C. If increased, can cause right heart failure
D. Is measured through routine pulmonary function tests
Correct answer:
Pulmonary vascular resistance (PVR) reflects opposition to blood flow in the pulmonary circulation, influenced by lung volume and vessel mechanics. At high lung volumes (near TLC), extra-alveolar vessels stretch and narrow, and alveolar capillaries compress, increasing PVR. At low volumes (near RV), these vessels are less stretched and more patent, lowering PVR, though this isn't the queried truth. The true statement is that increased PVR can lead to right heart failure, as seen in conditions like pulmonary hypertension or fibrosis, where elevated resistance overworks the right ventricle, causing cor pulmonale. PVR isn't measured by routine pulmonary function tests (e.g., spirometry), which assess airflow and volumes, not vascular pressures cardiac catheterization is required instead. The link to right heart failure is critical, as chronic high PVR elevates pulmonary artery pressure, straining the heart's ability to pump against it, a key pathophysiological consequence distinguishing this option as true amid the others' inaccuracies.
Regarding pulmonary vascular resistance, which one of the following is true?
A. Is low at high lung volumes
B. Is low at low lung volumes
C. If increased, can cause right heart failure
D. Is measured through routine pulmonary function tests
Correct answer:
Pulmonary vascular resistance (PVR) reflects opposition to blood flow in the pulmonary circulation, influenced by lung volume and vessel mechanics. At high lung volumes (near TLC), extra-alveolar vessels stretch and narrow, and alveolar capillaries compress, increasing PVR. At low volumes (near RV), these vessels are less stretched and more patent, lowering PVR, though this isn't the queried truth. The true statement is that increased PVR can lead to right heart failure, as seen in conditions like pulmonary hypertension or fibrosis, where elevated resistance overworks the right ventricle, causing cor pulmonale. PVR isn't measured by routine pulmonary function tests (e.g., spirometry), which assess airflow and volumes, not vascular pressures cardiac catheterization is required instead. The link to right heart failure is critical, as chronic high PVR elevates pulmonary artery pressure, straining the heart's ability to pump against it, a key pathophysiological consequence distinguishing this option as true amid the others' inaccuracies.
A client with suspected tuberculosis will most likely relate which clinical manifestations?
A. Fatigue, weight loss, low grade fevers, night sweats.
B. Dyspnea, chest pain, cough.
C. Rapid shallow breathing, prolonged labored expiration, stridor.
D. Dyspnea, hypoxemia, decreased pulmonary compliance.
Correct answer:
The correct answer is A. A client with suspected tuberculosis is likely to experience fatigue, weight loss, low-grade fevers, and night sweats due to the chronic infection affecting the body. Fatigue and weight loss are common symptoms of active tuberculosis due to the systemic impact of the infection. Low-grade fevers and night sweats are characteristic of tuberculosis due to the body's immune response. These symptoms are key indicators of tuberculosis infection.
Choices B, C, and D are incorrect because they describe symptoms that are not typically associated with tuberculosis. Dyspnea, chest pain, and cough (Choice B) are more commonly seen in respiratory conditions such as pneumonia or bronchitis. Rapid shallow breathing, prolonged labored expiration, and stridor (Choice C) are indicative of airway obstruction rather than tuberculosis. Dyspnea, hypoxemia, and decreased pulmonary compliance (Choice D) are more characteristic of conditions such as chronic obstructive pulmonary disease (COPD) rather than tuberculosis.
Fick's law depend on multiple factors, which one of them will have the most effect when observing the diffusion of different gases?
A. Partial pressure gradient
B. Temperature
C. Diffusion distance
D. Diffusion coefficient
Correct answer:
Fick's law of diffusion states that the rate of gas diffusion across a membrane (e.g., alveolar-capillary) is proportional to the surface area (A), diffusion coefficient (D), and partial pressure gradient (ΔP), and inversely proportional to diffusion distance (d): Rate = (A × D × ΔP) / d. When comparing different gases (e.g., O2 vs. CO2), the diffusion coefficient (D) varies most significantly, as it depends on gas solubility and molecular weight (D ∠solubility / √MW). CO2's solubility is ~20 times higher than O2's (0.51 vs. 0.024 ml/mmHg/L), though O2's molecular weight is slightly lower (32 vs. 44), making CO2 diffuse ~20 times faster despite similar gradients. Partial pressure gradient drives diffusion but is gas-specific and often comparable (e.g., O2: 100-40 mmHg, CO2: 46-40 mmHg). Temperature and distance affect all gases similarly in the lung. Thus, the diffusion coefficient has the most pronounced effect across different gases, explaining why CO2 equilibrates faster than O2 across the respiratory membrane.
Diffusion rate, per Fick's law, depends on surface area (choice A), concentration gradient (choice B), solubility (choice C), and membrane thickness (choice E), but not directly on molecular weight of gas (choice D), making D correct. Surface area increases diffusion by providing more space for gas exchange, as seen in alveoli. The concentration gradient (partial pressure difference) drives diffusion, e.g., Oâ‚‚ from alveoli to blood. Solubility affects how easily gases dissolve in the membrane, with COâ‚‚ diffusing faster than Oâ‚‚ due to higher solubility. Thickness inversely affects rate; thinner alveolar walls enhance diffusion. Molecular weight influences diffusion speed in free gas (Graham's law), but in the lung's aqueous environment, solubility dominates over molecular weight for Oâ‚‚ and COâ‚‚ exchange across membranes. Studies show diffusion capacity correlates with solubility and pressure gradients, not molecular weight, in physiological contexts, confirming D as the factor least affecting diffusion rate here.
LPN exams respiratory practice questions, set 2 for nursing students in the United States. Fifteen items. Five include answers and rationales in American English.
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